SSC 107, Fall 2002 – Chapter 7 Page 7-1 Chapter 7 - Gas Flow • • • • • • • • • Mechanisms of flow Fick's Law Methods for measuring D Diffusion equations Diffusion to plant roots Consumption or production of gases Aeration Other diffusion processes Water vapor movement ______________________________________________________________________ Important Soil Gases O2 CO2 O2 CO2 H2S SO2 NH3 N2 N2O NO CxHy SSC 107, Fall 2002 – Chapter 7 Page 7-2 An example of diffusion processes related to contaminants in the vadose zone SSC 107, Fall 2002 – Chapter 7 Page 7-3 Mechanisms for transfer of gases 1. Mass flow in vapor phase a. b. c. d. Barometric pressure changes Wind Irrigation or rain Production from other chemicals 2. Mass flow in dissolved (liquid) phase a. Movement with water 3. Diffusion in liquid phase a. 103 - 104 smaller than diffusion in vapor phase b. Important in transport of O2 to roots and anoxic denitrification sites 4. Diffusion in vapor phase a. Probably main mechanism Fick's Law (for diffusion of gases) mg = = - a dCg Jg Dg At dz Fick's law assumes that gases are dilute and that there is equimolar counter diffusion of each gas. a Dg is the diffusion coefficient in air without soil and C g is concentration of gas. What happens to Dag for soil? Le L Le is the effective length SSC 107, Fall 2002 – Chapter 7 Page 7-4 In soil, not air, the equation becomes mg ∆Cg = − Dag Aet Le where Ae is the effective pore area. The soil-air content, a, is a= vol gas Ae Le = total vol A L Ae = or aAL Le Thus mg = - a LDag ∆Cg At Le Le Multiplying top & bottom by L gives Jg = - a L Let D = a Le s g Thus Jg = - Dsg L2 Dag ∆Cg Le2 L 2 Dag ∆ Cg or Jg = - Dsg dCg L dz s Dg is the apparent diffusion coefficient for soil or soil-gas diffusivity Self diffusion coefficient is for a gas into itself Mutual (or binary) diffusion coefficient is for one gas diffusing into a different gas L Le 2 is called the tortuosity factor For some cases Dsg = 0.66 a Dag (not too good when a is small) SSC 107, Fall 2002 – Chapter 7 Page 7-5 Thus 2 2 L cm soil = 0.66 2 cm air Le Penman Other Relationships s 3/2 a Marshall Dg = a Dg s 4/3 a Millington Dg = γ a Dg Currie Dg = a Dg µ s a 10/3 a a D = 2 Dg φ s g Dsg = d 3 2a100 Millington and Quirk + 0.04a100 iFGH a a IJK 2+3/ b D ag Moldrup et al. (1999) 100 where a100 is the soil-air content at a soil-water pressure head of –100 cm of water and b is the slope of the Campbell water retention function. If b is not known, it can be estimated from the clay fraction given by the following equation: b = 13.5 CF + 3.5 where CF is the clay fraction. Effect of temperature on Dg T2 DT 2 = DT1 T1 n Where T is in degrees Kelvin. The value of n has been found to be about 1.72-1.75. SSC 107, Fall 2002 – Chapter 7 Page 7-6 0. 5 Dgs/Dga Penman Millington & Quirk 0 0 Soil-air content (a) 0.5 Two relationships of soil gas diffusion coefficient to soil-air content. The SWC dependent model is the one by Moldrup et al. (1999) SSC 107, Fall 2002 – Chapter 7 Page 7-7 An apparatus for measuring the diffusion coefficient for soil Diagram giving initial and boundary conditions C=C0 t≥0 X=0 Soil Core X=-L C=C0 t=0 C=Ci t=0 C=f(t) t›0 Diffusion Chamber X=-(L+a) Position A Soil Core Slide - Horizontal Diffusion Chamber Sample Port SSC 107, Fall 2002 – Chapter 7 Page 7-8 Position B Soil Core Diffusion Chamber Sample Port Method of measuring Dsg in lab - Jg = - dC mg = - Dsg g At dz (flow down) mg - mass of gas Cg - concentration in chamber - dmg dC = - Dsg A g dt dz V - volume of chamber mg = Cg V s dC D A dCg ∴ g =+ g dt V dz Co - Concentration of tracer gas dCg Cg - Co ≅ dz -L at the top of the core L - Length of soil core s g dCg D A =(Cg - Co ) dt VL Rearranging SSC 107, Fall 2002 – Chapter 7 Page 7-9 Dsg A dCg =- dt and integrating Cg - Co VL cg ∫ ci t Ds A dCg = - g ∫ dt Cg - Co VL o Where Ci is initial concentration in chamber at t=0 Dsg A t Cg ln (Cg − C 0 ) Ci = - t0 VL Ds A ln (Cg - Co ) - ln (Ci - Co ) = - g t VL Cg - Co Dsg A ln t =- Ci - Co VL If Ci = 0 C - C Ds A ln o g = - g t Co VL dCg Cg - Co ≠ dz -L Also, equation does not take into account change in storage of gas in soil core. Equation not valid for small times because SSC 107, Fall 2002 – Chapter 7 Page 7-10 0 -0.02 -0.04 ln [(Cg - Co)/(Ci - Co)] -0.06 -0.08 -0.10 0 0.5 Time (hours) 1.0 A plot of ln [(Cg - Co)/(Ci - Co)] vs. time using hypothetical data from a soil core with values of a= 0.1 m3 m-3, L = 76 mm, A = 4540 mm2, and V = 0.5 L. SSC 107, Fall 2002 – Chapter 7 Diffusion equations With concentration on fluid basis Steady State s J g = - Dg dCg dz Cg is concentration on fluid basis and units are g gas/cm3 soil air 3 g gas s g gas/ cm air = D g 2 cm soil cm soil s ∴ Dsg = 3 cm air cm soil s Transient State ∆ storage = ∆ flux a ∂ Cg ∂J =- g ∂t dz a 2 ∂ Cg ∂ Cg = Dsg ∂t ∂z 2 2 ∂ Cg ∂ Cg = Dm ∂t ∂z 2 ∴ Dm = cm 2 soil s s Dg Dm = a Page 7-11 SSC 107, Fall 2002 – Chapter 7 With concentration on soil basis use Cm Steady State J g = - Dm dCm dz Cm - g gas/cm3 soil Transient State 2 ∂ Cm ∂ Cm = Dm ∂t ∂z 2 2 g g cm soil = 3 3 2 s cm soil cm soil cm soil s Page 7-12 SSC 107, Fall 2002 – Chapter 7 Page 7-13 Dissolution of gas in soil water and adsorption on soil 2 ∂ Cg ∂ s ∂ Cg ∂ Sw a = Dg - Ss 2 ∂t ∂z ∂t ∂t where Sw (g gas / cm3 soil) is amount of gas dissolved in water and Ss (g gas / cm3 soil) is amount of gas adsorbed to soil solids. The relationships between gas phase and water phase concentrations are Cg = K H Sw / θv or Sw = Cg θv / K H where K H is the "dimensionless" Henry's coefficient (cm3 water/cm3 air). The relationship between the gas dissolved in the liquid phase and that in the sorbed phase is Ss / ρb = Kd Sw / θv where Kd (cm3 water /g soil) is the liquid/soil partition coefficient. Substituting Sw from the equation above gives Ss = Kd ρb Cg / K H Taking the derivatives of S w and S s with respect to time and substituting into the original equation gives 2 θ v K dρ b ∂ Cg s ∂ Cg a = + + D g KH K H ∂t ∂z 2 Dividing both sides by a gives 2 K d ρ b ∂ Cg θv ∂ Cg 1 + + = D m aK aK H ∂t ∂z 2 H SSC 107, Fall 2002 – Chapter 7 Page 7-14 or ∂ Cg Dm ∂ 2 Cg = R ∂z 2 ∂t where Dm = Dsg / a and R is the retardation coefficient given by R =1+ Kρ θv + d b aK H aK H Consumption or Production of Gases - O2 consumed - CO2 produced - some gases adsorbed - some gases react 2 ∂ Cg s ∂ Cg a = Dg + r g (z, t) ∂t ∂z 2 r g (z, t) is sink or source terms to take consumption or production into account SSC 107, Fall 2002 – Chapter 7 Page 7-15 A steady-state solution for gas diffusion and consumption Jg = − D sg dCg dz For O2 ∂Cg ∂ 2 Cg = Dm 2 − S( z, t ) ∂t ∂z where S(z,t) = rg(z,t)/a and rg is the gas reaction rate. Assume S(z, t) = α, α is a constant O2 consumption rate assume steady state, ∂ Cg =0 ∂t 2 d Cg = α, Dm 2 dz Integrate once with respect to z ∫d C 2 dz g 2 dz = ∫ α Dm dz, dCg α = z + c1 dz Dm where c1 is a constant of integration. 2 d Cg α = 2 dz Dm SSC 107, Fall 2002 – Chapter 7 Page 7-16 Integrate again with respect to z ∫ ddzC g dz = ∫ α Dm ∫ zdz + c1 dz to give Cg = α 2 Dm 2 z + c1 z + c 2 where c2 is an additional constant of integration. At z = 0, Cg = Co. Therefore, Co = C2, and Cg = α 2 Dm 2 z + c1 z + Co Assume we have a finite column with a closed bottom or a water table at depth L, flux at depth L = 0 or dCg/dz = 0. Substituting dCg/dz = 0 in equation determined after first integration gives 0= α Dm c1 = - L + c1 α L Dm α 2 αL z + Co Cg = z 2 Dm Dm SSC 107, Fall 2002 – Chapter 7 Page 7-17 Oxygen profiles in soils as related to degree of biological activity and the soil gaseous diffusion coefficient. Curve Dgs/Dga Degree of Activity (liters/m3 day) 10 5 10 5 1 2 3 4 0.06 0.06 0.25 0.25 0 Soil Depth (m) 1 2 3 4 1 1 5 Oxygen (%) 2 1 SSC 107, Fall 2002 – Chapter 7 Page 7-18 Aeration - Effects on Plants 1. O2 needed for root respiration - critical values of flux 2. Good aeration is essential for maximum H2O absorption. Sudden reduction of O2 will cause growing plant to wilt. 3. CO2 retards uptake of nutrients. Reduction follows K>N>P>Ca>Mg 4. CO2 & H2O form carbonic acid which increases the solubility of many soil minerals. Some ions may become toxic to plants 5. Growth of roots limited by either lack of O2 or buildup of CO2 6. O2 needs increase with temperature 7. O2 needs increase as soil-water pressure head increases - physical process-meaning at lower air content, gradients must be increased 8. Rate of O2 flux (supply) and CO2 removal is most important Diffusion to plant roots - O2 must diffuse through water films to reach root - Mechanism simulated by measuring O2 diffusion to a microelectrode Jg = It n * F′A This is the oxygen diffusion rate (ODR) It is current (amps) in time t n* = 4 for O2 molecules F' is the Faraday constant = 96,500 coulombs A is the surface area of the electrode s Dg cannot be determined. SSC 107, Fall 2002 – Chapter 7 Page 7-19 Several figures related to aeration follow: Oxygen diffusion rates at a given soil depth as a function of depth of water table. (Williamson and van Schilfgaarde, 1965). SSC 107, Fall 2002 – Chapter 7 Above figure from Glinski and Stepniewski (1983) Page 7-20 SSC 107, Fall 2002 – Chapter 7 Page 7-21 Other Diffusion Processes -Flooded soil or sediments • O2 diffusion • NH3 volatilization • Solute diffusion A diagram showing diffusion processes in flooded soil (Reddy et al.) SSC 107, Fall 2002 – Chapter 7 Page 7-22 - Denitrification Aggregate or anoxic pocket or "hot spot" O2 Anoxic Zone NO3 N2O or N2 Also - Diffusion of radon gas from soil into dwellings - Volatilization of pesticides or volatile organics from soil __________________________________________________ Stagnant Air Layer ________________________________________________ Soil Surface Soil + Pesticide Pesticide SSC 107, Fall 2002 – Chapter 7 Page 7-23 Diagrams concerning volatile organic chemical transport processes follow: SSC 107, Fall 2002 – Chapter 7 Page 7-24 Water Vapor Movement J wv = - Dv d ρv dz ρv- vapor density in gaseous phase Dv - diffusion coefficient for water vapor in soil corrected for tortuosity (See book) Vapor density gradients caused by 1. Differences in matric potential and solute potential 2. Temperature differences Vapor density, Dv, in grams of vapor per cubic cm of pore space (g/cm3) at various temperatures and at two soil-water potentials. Water Potential Temperature (C) 15 18 20 21 22 23 24 25 30 35 -0.1 bar (-9.8 kPa) 12.83 x 10-6 15.37 x 10-6 17.30 x 10-6 18.34 x 10-6 19.43 x 10-6 20.58 x 10-6 21.78 x 10-6 23.05 x 10-6 30.38 x 10-6 39.63 x 10-6 -15 bars (-1500 kPa) 12.70 x 10-6 15.22 x 10-6 17.13 x 10-6 18.16 x 10-6 19.24 x 10-6 20.37 x 10-6 21.56 x 10-6 22.82 x 10-6 30.08 x 10-6 39.23 x 10-6 at - 0.1 bars have 100% relative humidity at - 15 bars have 98.98% relative humidity ... Differences in water potential will have little effect on vapor transport Temperature differences have the much larger effect, but still little difference in effects of water potential over the range between - 0.1 and - 15 bars at different temperatures Appreciable vapor phase water flow will occur in the field surface soil due to the development of large vapor density gradients
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